Infallible Code

Destide@feddit.uk · 5 个月前

redxef@feddit.org · 5 个月前

def is_even(n: int) -> bool:
    if n < 0:
        return is_even(-n)
    r = True
    for _ in range(n):
        r = not r
    return r

OddMinus1@sh.itjust.works · 5 个月前

Could also be done recursive, I guess?

boolean isEven(int n) {
  if (n == 0) {
    return true;
  } else {
    return !isEven(Math.abs(n - 1));
  }
}

⛓️‍💥@sh.itjust.works · 5 个月前

deleted by creator

dragonlobster@programming.dev · 5 个月前

He loves me, he loves me not

vandsjov@feddit.dk · 5 个月前

No, no, I would convert the number to a string and just check the last char to see if it was even or not.